1157A - Reachable Numbers - CodeForces Solution


implementation *1100

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Python Code:

n = int(input())


def f(num):
    num += 1
    while num % 10 == 0:
        num //= 10

    return num

dostizh_nums = set()

while n not in dostizh_nums:
    dostizh_nums.add(n)
    n = f(n)

print(len(dostizh_nums))

C++ Code:

#include <bits/stdc++.h>

using namespace std;
#define ll long long
#define el '\n'
#define ll long long
#ifndef ONLINE_JUDGE
#include "Debug.cpp"
#else
#define debug(...) 42
#endif
void solve ( ) {
    int n;cin>>n;
    ll cnt = 9 ;
    while(n>=10)
    {
        cnt+=10-n%10 ;
        n+=10-n%10 ;
        while(n%10==0) {
            n/=10 ;
        }
    }
    cout<<cnt<<el ;
}
int main ( ) {
    ios_base::sync_with_stdio ( 0 );
    cin.tie ( 0 );
    cout.tie ( 0 );
    int t = 1;
//    cin >> t;
    for ( int i = 0; i < t; i ++ ) {
        solve ( );
    }
}


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